R= current speed 5r = boat speed T = time
Travel speed downstream = 5r+r = 375/(t+1) Travel speed upstrean = 5r-r=225/t R= 375/(6t+6) R=225/4t 225/4t = 375/(6t+6)
Solve for T and then plug in T into R=225/t to determine R and then the speed of the boat = 5r.
Wojtek
> -----Original Message-----
> From: lbo-talk-bounces at lbo-talk.org
> [mailto:lbo-talk-bounces at lbo-talk.org] On Behalf Of joanna
> Sent: Wednesday, February 22, 2006 10:36 PM
> To: lbo-talk at lbo-talk.org; 123hop at comcast.net
> Subject: [lbo-talk] math problem...
>
> Sorry, it's driving me crazy. Can anyone help with below.
> The equations I came up with don't seem to be right.
>
> Thanks,
> Joanna
> ___________________________________________
>
> Boat can travel 5 times speed of current.
> It can travel 375 miles downriver in 1 hour more than it
> takes to travel
> 225 miles upriver.
> What is speed of boat in still water?
>
> r = speed of current
> t = time
>
> 375 = 6r ( t + 1)
> 275 = 4r (t)
>
>
>
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